192.168.1.0/29
11111111.11111111.11111111.11111000
255.255.255.248
1. Jumlah subnet = 2^x
= 2^5
= 32
2. Jumlah host = 2^y
= 2^3
= 8
3. Blok subnet = 256-248
= 8
berarti total ada 32 subnet dimulai dari 0,8,16,24,32,40,48,56,64,72, 80,88,96,104,112,120,128,136,144,152,160,168,176,184,192,200,208,216,224,232,240,248
karena absen saya 13 maka saya menggunakan angka ke 13 yaitu 96
jadi...
subnet = 192.168.1.96
host pertama = 192.168.1.97
host terakhir = 192.168.1.102
broadcast = 192.168.1.103
